x^2-10x-59=0

Solution for x^2-10x-59=0 equation:

x^2-10x-59=0

a = 1; b = -10; c = -59;
Δ = b2-4ac
Δ = -102-4·1·(-59)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{21}}{2*1}=\frac{10-4\sqrt{21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{21}}{2*1}=\frac{10+4\sqrt{21}}{2}
$